a simple pendulum completes 50 oscillations in one minutes find its frequency and time period
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1
Answer:
No. of oscillations = N= 50
time taken for oscillations= t = 1 min or 60 sec
frequency, f=N/t
=50/60
= 5/6 or 0.833 Hz or 0.833 sec^-1
Time period,T= 1/f
= 1/0.833
= 1.2 sec
Answered by
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(1) Frequency = oscillation/Time
Frequency = 50/60
Frequency = 5/6Hz
(2) Time period = Time/Oscillation
Time Period = 60/50
Time Period = 6/5sec
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