Question

A simple pendulum completes one oscillation in 2.0 seconds calculate it's length where g=9.8m/second square

Answer 1

Answer:

For second’s pendulum T=2sec

G=9.8 m/sec

T=2 pi *root l/root g

L= gt^2/4 pi^2

L= 9.8*2*2/4*3.14*3.14

L=0.994m

L=1 m (approx)

Answer 2

Time period of the oscillation = 2 seconds (given here)

$t \: = 2\pi \sqrt[]{ \frac{l}{g} }$

This is the formula of time period of one oscillation of a simple pendulum.

You may find the derivation of this anywhere on the web or any classical mechanics Physics Book for high school.

Well,

putting in the values,

2 = 2π√Length/g

1/π^2 = Length / 9.8

So,

Length of the simple pendulum is approximately 1.004 metres but you can write for the answer as 1 metre.