Physics, asked by saijoshita5, 1 month ago

A simple pendulum designed on the moon as a
seconds pendulum is taken to a planet where the
acceleration due to gravity on the surface is twice
that on the earth. If g on earth : g on moon = 6 : 1, find the
period of oscillation of the pendulum on the planet
mentioned above.

Please answer only if you know the answer.

Answers

Answered by rajeshrkrkraju

1

Answer:

find the attached answer

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