Question

A simple pendulum has a frequency of 6
vibrations per second. An observer displaces
the pendulum at rest and simultaneously fires
a gun. He hears an echo from a wall when the
pendulum completes 10 vibrations. Find the
distance between the wall and the observer if
the speed of sound is 330 m s-1 in air.

I want this to be solved in copy​

Answer 1

Explanation:

Time taken for 1 vibration = 1/5 s 

Time taken for 8 vibrations = 8/5 s 

We know,  

2d = vt 

Therfore, 

D= vt/2 [where d= distance between the observer and the cliff] 

V = velocity of sound 

T= time taken for the sound to go and return 

D = (340 * 8 / 5*2) m  

D = 272 m 

So the distance between the cliff and observer is 272

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