a simple pendulum has a string of length l and bob of mass m. when the bob is at its lowest position, it is given the minimum horizontal speed necessary for it to move in a circular path about the point of suspension. The tension in the string at the lowest position of the Bob is
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this question solve by method of conservation of energy.
at the highest position tension in string is zero .now we proceed
mg=mv^2/l at tje highest position
v^2=gl
now at the lowest position
apply conservation of energy
1/2mv^2+mg.2l=1/2mv'^2
v'2=5gl
where v'is velocity of bob at lowest position
now, T=6mg
at the highest position tension in string is zero .now we proceed
mg=mv^2/l at tje highest position
v^2=gl
now at the lowest position
apply conservation of energy
1/2mv^2+mg.2l=1/2mv'^2
v'2=5gl
where v'is velocity of bob at lowest position
now, T=6mg
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