A simple pendulum has a time period T1 when on Earths surface and T2 when
taken to a height R above the Earths surface, where R is the radius of the earth.
The value of T2/T1 is
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0
Answer:
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Answered by
0
Explanation:
Time period of a simple pendulum =2π
g
l
⇒g on earth's surface =
R
2
GM
g on a height R above earth's surface =
(2R)
2
GM
⇒T
1
(time period on earth's surface ) =2π
GM
l(R
2
)
T
2
(time period at a height
′
h
′
above earth's surface ) =2π
GM
l(2R)
2
⇒
T
1
T
2
=
4
=2.
Hence, the answer is 2.
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