A simple pendulum has time period 't'. Its time period in a
lift which is moving upwards with acceleration 3 ms⁻² is
(a) t√9.8/12.8
(b) t√12.8/9.8
(c) t√9.8/6.8
(d) t√6.8/9.8
Answers
Answered by
0
Answer:
t∝
9.8
1
,t
′
∝
12.8
1
(∵g
′
=9.8+3=12.8)
∴
t
t
′
=
12.8
9.8
⇒t
′
=
12.8
9.8
t
Explanation:
answer is b
Answered by
0
Answer:
(a) t√9.8/12.8 is the correct answer.
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