Question

A simple pendulum has time period t1 the point of suspension is now moved upwards according to the relation y=kt^2 (k=2m/s^2)where y is the vertical displacement the time period now becomes t2 then the rTio of t1^2/t2^2is

Answer 1

Y=kt^2

d^2y/dt^2 = 2k ,as k=1

Then, ay=2m/s^2

T=2π√l/g

T`=2π√l/g+ay

Hence, T/T`=10+2/10=6/5