Question

A simple pendulum is carrying a Bob of mass M it is pulled through an angle 45 degree from its mean position the horizontal force required to keep it under equilibrium at this new position is

Answer 1

Answer:

The horizontal force required to keep the bob in equilibrium is Mg

Explanation:

Let the horizontal force required to keep it in equilibrium is F

If the tension in the string is T then resolving T into two components and balancing teh forces

In the vertical direction

$T\sin45^\circ=Mg$

$\implies \frac{T}{\sqrt{2}}=Mg$

$\implies T=Mg\sqrt{2}$

In the horizontal direction

$T\cos45^\circ=F$

$\implies Mg\sqrt{2}\times \frac{1}{\sqrt{2}}=F$

$\implies F=Mg$

Thus, the horizontal force required to keep the bob in equilibrium is Mg

Hope this helps.