Question

A simple pendulum is made by suspending a bob of mass 200g by a string of length 1m. Calculate its time period at a place where g = 10m/s^2. ( I have a physics exam and would hence appreciate a prompt response)

Answer 1

mass=200g 
gravity=10 m/s²
L=1m
So period (T)?

use this formula:
$T=2\pi \sqrt{ \frac{L}{g} } \\\ T=2(3,14) \sqrt{ \frac{1}{10} } \\\ T=6,28. \sqrt{0,1} \\\ T=6,28(0,3) \\\ T=1,98 s$