Question

A simple pendulum is made by suspending a bob of mass 500g by a string of length 1m. Calculate it's time period at a place where g= 10m/s²

Answer 1

Time period of a simple pendulum is given by

T=2 π √L/g

where     L=length of pendulum = 1 m
               g= gravitation=10 m/s²

∴ T=2 π √1/10

T=1.98 sec ≈ 2 sec

Hope it helps you.

P.S. It is not dependent upon the mass of the bob

Answer 2

Answer:

The time period at a place is 2 sec.

Explanation:

The time period of a simple pendulum exists described as the time taken by the pendulum to complete one full oscillation and is represented by “T”.

The period of a simple pendulum exists given by

$T=2 \Pi \sqrt{L} / g$

where L is the length of the pendulum

Length of pendulum = 1 m

g be the gravitation

gravitation $=10 m / \mathrm{s}^{2}$

Therefore, $\mathrm{T}=2 \pi \sqrt{1} / 10$

T = 1.98 sec

= 2 sec

Therefore, the time period at a place is 2 sec.

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