a simple pendulum is suspended from a fixed point O through a light string of fixed length l . it is projected horizontally from lowest point with speed u=√2gl. find the angel with the vertical at which acceleration is directed horizontal.
a)tan-¹1
b)tan-¹ √2
c)sin-¹ 1/√3
d)cos-¹ √2
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option d i hope this will help you
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