A simple pendulum is suspended from the roof of a trolley which moves in a horizontal direction with an accelaration a , then the time period is given by t = 2 pi sqrt ( l / g' ), where g' will be equal to ?
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The pendulum is suspended from the roof of a trolley which is moving in horizontal direction with accelerationa
Hence the force acting will be
F=mai−mgj
Let θ angle between the horizontal and vertical then
tanθ=
mg
ma
Then the value of g
′
=
g
2
+a
2
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