Question

A simple pendulum is taken from earth to moon .will it go faster or slower

Answer 1

faster

is your true answer

thanks

Answer 2

A simple pendulum, taken from earth to moon will go slower.

For a simple pendulum, we know, its time period (T) is given as:

T = 2П$\sqrt{\frac{l}{g} }$                           ...(1)

l = length of the rod/wire of the pendulum ( = 2m for simple pendulum)

g = acceleration due to gravity on earth.

Representing acceleration due to gravity on moon as g', the time period (T') of the pendulum on moon is represented as:

T' = 2П$\sqrt{\frac{l}{g'} }$                            ...(2)

As we know, acceleration due to gravity on moon is 1/6 th times that on earth, so g' = g/6.

Putting g' = g/6 in eqn. (2),

T' = 2П$\sqrt{\frac{l}{\frac{g}{6} } }$

⇒ T' = 2П$\sqrt{\frac{6l}{g} }$                       ...(3)

When we compare (1) and (3), we can conclude that

T' > T

or, the time taken for one oscillation on moon would be more than that on earth, so, the pendulum becomes slower.