A simple pendulum, made of a string of length land a bob of
mass m. is released from a small angle On It strikes a block of
mass M, kept on a horizontal surface at its lowest point of
oscillations, elastically. It bounces back and goes up to an
angle 0,- The M is given by:
m0,
+0,
0, -0,
0. +
(1) 20.-,
(2)
m[ 0,
(3)
0, +8,
0,-,
(4) 210, +0,
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11th
Physics
Work, Energy and Power
Collisions in Two Dimensions
A simple pendulum, made of ...
PHYSICS
A simple pendulum, made of a string of length l and a bob of mass m, is released from a small angle θ
0
. It strikes a block of mass M, kept on a horizontal surface at its lowest point of oscillations, elastically. It bounces back and goes up to an angle θ
1
. Then M is given by :
MEDIUM
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ANSWER
u=
2gl(1−cosθ
o
)
........ (1)
v = velocity of ball after collision
v=
m+M
m−M
u
Since ball rises upto height θ
1
v=
2gl(1−cosθ
1
)
=
m+M
m−M
u ......... (2)
From (1) and (2)
m+M
m−M
=
1−cosθ
0
1−cosθ
1
=
sin
2
θ
0
sin
2
θ
1
m
M
=
θ
0
+θ
1
θ
0
−θ
1
M=(
θ
0
+θ
1
θ
0
−θ
1
)m
solution