Question

A simple pendulum makes 180 oscillations in 30 seconds.Calculate the frequency and time period of it's oscillation

Answer 1

no. of oscillations made in 30 sec. = 180

No. Of oscillations made in one sec. =

=180/30 =6

This is frequency,i.e.= 6 Hz

Now time period = 1/Frequency

T = 1/6 =0.16 sec.

Answer 2

The frequency and time period of its oscillation are 6 Hz and 0.167 s respectively.

Explanation:

Given that,

Number of oscillation, n = 180

Time, t = 30 s

We need to find the frequency and time period of its oscillation. The total number of oscillation per second is called frequency. It is given by :

$f=\dfrac{n}{t}$

$f=\dfrac{180}{30}$

f = 6 Hz

The time period of oscillation is given by :

$T=\dfrac{1}{f}$

$T=\dfrac{1}{6}$

T = 0.167 s

So, the frequency and time period of its oscillation are 6 Hz and 0.167 s respectively. Hence, this is the required solution.

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