A simple pendulum makes 20 oscillations in one sec-
ond on the surface of the earth. Determine the time
period of the simple pendulum on the surface of a
planet where the acceleration due to gravity is one
fourth of the acceleration due to gravity on the sur-
face of the earth.
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Answer:
On surface of moon, acceleration due to gravity is g/6. Time period of seconds pendulum on earth is 2 seconds.
On Earth, 2=2π
g
l
On moon,T
moon
=2π
6
g
l
Dividing the above two equations, we get, T
moon
=2
6
s
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