Question

A simple pendulum makes 40 ossilations in 20 seconds . what is the time period and frequency​

Answer 1

Answer:

• Time period = 2 seconds
• Frequency = 0.5Hertz

Explanation:

Given,

A simple pendulum makes 40 oscillations in 20 seconds.

Find the time period and frequency.

Time period is given by,

$\rm = \dfrac{Number \: of \: oscillations}{Time \: taken}$

$= \dfrac{40}{20}$

$\rm = 2sec$

Frequency is given by,

$\rm = \dfrac{1}{Time \: period}$

$= \dfrac{1}{2}$

$\rm = 0.5Hz$

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Formulae:

• Time period :- $\rm \dfrac{Number \: of \: oscillations}{Time \: taken}$
• Frequency :- $\rm \dfrac{1}{Time \: period}$

Units:

• Time period is denotes by sec.
• S.I. unit of frequency is Hertz(Hz)

Answer 2

Time period = 2 seconds and Frequency is 0.5 Heartz.

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Explanation : 40 ossilations takes 20 seconds.

we have to find ( i ) Time period and ( ii ) frequency.

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Time period = Time taken for 1 ossillation .

if 40 ossilations take 20 seconds.. then,

• 1 ossilation = 40/20 = 2 seconds.

now calculating frequency ;

Frequency = Number of ossilations in 1 second.

• 1 second = 20 / 40 ossilations
• Frequency = 20 /40 s‐¹.
• = 0.5Hź

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