Question

A simple pendulum makes 80 oscillations in 40 seconds. What is the time period and frequency of its oscillation?


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Answer 1

Explanation:

Answer: The time period of the pendulum is 0.5 s. Explanation: In the given problem, a simple pendulum takes 80 seconds to complete 40 oscillation. To find the frequency, use the unitary method.

Answer 2

$\Large\sf\green{Given:}$

A simple pendulum makes 80 oscillations in 40 seconds.

$\Large\sf\green{To\:find:}$

Time period

Frequency

$\Large\sf\green{Solution:}$

$\tt\pink{No.\: of \: oscillations,\:N = 80}$

$\tt\pink{Time\: taken,\:t = 40\:seconds}$

Let t is the time period of oscillation.The total number of oscillations per unit time is called frequency.

$\sf f = \dfrac{80}{40}$

$\sf f = \cancel\dfrac{80}{40}$

$\sf f = 2Hz$

$\tt\blue{Therefore,\:Frequency(f) = 2Hz}$

The realtion between the time period and frequency is given by :

$\sf f = \dfrac{1}{t}$

$\sf t = \dfrac{1}{2Hz}$

$\sf t= 0.5$

$\tt\blue{Therefore,\:Time\:Period=0.5\:sec}$

$\bf\red{Time\:period\:of\:oscillations = 0.5s }$

$\bf\red{Frequency\:of\:oscillations = 2Hz }$