Question

A simple pendulum of length 100 cm performs S.H.M. Find the restoring force acting on its bob of mass 50 g when the displacement from the mean position is 3 cm.​

Answer 1

$\huge \orange \star \pink{ \textsf{ \textbf {\underline{Solution :- }}}}$

Length = 10cm

m = 50g = 5 × 10-²kg

x = 3cm

g = 9.8m/s²

We know that,Restoring Force

F = mg sinϴ = mgϴ

$\sf \: \: \: \: \: \: \implies(5 \times {10}^{ - 2})(9.8) \large \bigg( \frac{3}{100} \bigg)$

$\sf\: \: \: \: \: \: \implies1.47 \times {10}^{ - 2}N \:$

Answer 2

$\huge\mathrm{Answer}$

Given ➡

Length ( L ) = 100 cm = 1 m

Mass ( m ) = 50 g = ( 50 / 1000 ) kg

Displacement ( d ) = 3 cm = 0.03 m

Solution ➡

We know that g = 9.8 m/s²

Restoring force = mgsinϴ

=> Restoring force = 0.05 × 9.8 × 0.03

=> Restoring force = 0.0147 N

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Simple harmonic motion is a very type of periodic oscillation where the acceleration is directly proportional to the displacement