A simple pendulum of length 2 m oscillates with an angular amplitude of 4° .Find the velocity of its bob when it passes through the position of equilibrium.
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Kinetic energy = Potential energy
2
1
mv
2
=mgh
h=
2g
v
2
L(1−cosθ)=
2g
v
2
⇒cosθ=1−
2gL
v
2
=1−
2×10×2
4
2
=
5
3
⇒θ=cos
−1
(
5
3
)=53
o
Angle is 53
o
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