Question

A simple pendulum of length 4.9 m has a Bob of mass 100 g, calculate its time period at a place where g =10 meter per second​

Answer 1

Answer:

T= 4.40 s

Explanation:

$T=2\pi \sqrt{\frac{l}{g}} \\T=2\pi \sqrt{\frac{4.9}{10}}\\T= 4.40 s$