A simple pendulum of length 40cm subtends 60° at the vertex in one full oscillation.What will be the shortest distance between the initial position and the final position of the bob
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the shortest distance. hope u understand any doubt ping me
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Edwinabraham:
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Answer:
Given,
OA=OC= length of pendulum =40 cm,∠AOC=60
0
In triangle OBC,
=30
0
Here, OC=hypotenuse
AB=perpendicular
BC=base
We know,
40=2BC
BC=20 cm
Therefore,
length of AC=2(BC)
=2(20)=40 cm
Therefore, the shortest distance between the initial position and the final position of the bob =40 cm
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