Question

A simple pendulum of length carries a bob of mass m. If the breaking strength of the string is 2 mg, the maximum angular amplitude from the vertical can be

Answer 1

Answer:

The answer will be 60 degree

Explanation:

According to the problem the length of the pendulum let r,

and the mas of the bob is given

Now let the tension of the string is t

Now t at lowest point

t = mv^2/r +mg

As the strength of the string is given

Therefore

2mg = mv^2/r+mg

=> v = √rg

Now we know that ,

the potential energy at the highest point = the kinetic energy at the lowest point

=> mgl(1-cosθ) = 1/2 m (√rg)^2

=> cosθ = 1/2 = 60 degree

Answer 2

Answer:

60

Explanation:

I hope it's helpful to you