Physics, asked by jtanmay1743, 6 months ago

A simple pendulum of length l has a bob of mass m, with a charge q on it A vertical sheet of charge, with surface charge
density sigma passes through the points of suspension. At equilibrium, the string makes an angle theta with the vertical, then :

Answers

Answered by Trushangi
0

Explanation:

A simple pendulum of length l has a bob of mass m, with a charge q on it. A vertical sheet of charge, with charge σ per unit area, passes through the point of suspension of the pendulum. At equilibrium, the string makes an angle θ with the vertical. Its time period of oscillation is T in this position. (a) tan θ = σq/2ε0mg (b) tan θ = σq/ε0mg (c) T < 2π√l/g (d) T > 2π√l/gRead more on Sarthaks.com - https://www.sarthaks.com/552370/a-simple-pendulum-of-length-l-has-a-bob-of-mass-with-a-charge-q-on-it-a-vertical-sheet-of-charge

Answered by sujatg6
0

Answer:

Correct Answer is: (a) tan θ = σq/2ε0mg, (c) T < 2π√l/g E = σ/2ε0, T0cos θ = mg, T0sin θ = qE As T0 > mg,

the effective value of g is increased.

Hence, time period of oscillation decreases.

Explanation:

mark me as brainliest

Similar questions