Question

A simple pendulum of length l has a time period t for small oscillation. A fixed obstacle is placed directly below the point of suspension, so that only the lower quarter of the string continues oscillations. The pendulum is released from rest at a certain point o. The period of oscillation (assuming small angles) is found to be . Find n.

Answer 1

T' = 1/2( 2π√l/g + 2π√l/4/g )

= 1/2 ( T + T/2 )

= 3T/4