A simple pendulum of length ‘L’ is set in to oscillation. The time period of oscillation is ‘T’ s. What will be the time period of the pendulum if the length is increased by 4 times?
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Answer:
2T
Explanation:
T=2π√l/g
so new T'=2π√4l/g
=2×2π√l/g
=2T
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