Question

a simple pendulum of mass m and length l is held in position at an angle theta with the vertical if it is released from this position find the speed with which it will pass the lowest position​

Answer 1

Explanation:

Do refer to the work out attached above.

Answer 2

i hope this helped you.

The answer is

$\sqrt{2g l \: (1 - cosx} )$

here x is the angle i.e. theta