Physics, asked by akp903, 1 year ago

a simple pendulum performs simple harmonic motion about x= 0 with an amplitude a time period T .the speed of the pendulum at x= a/2 is ​

Answers

Answered by nasir1952sah
0

Answer:

As simple pendulum performs simple harmonic motion.

∴velocity,v=ω  

a  

2

−x  

2

 

​  

 

At, x=  

2

a

​  

 

v=  

T

​  

 

a  

2

−(  

2

a

​  

)  

2

 

​  

=  

T

​  

 

2

3a  

2

 

​  

 

​  

=  

T

πa  

3

Explanation:

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