Question

A simple pendulum with a brass bob has a time period T. the bob is now immersed in a non viscous fluid and oscillated .if the density of liquid is 1/9 of the brass. find the time period of simple pendulum

Answer 1

Density of the liquid = (1/8) ρ

Where ρ be the density of the brass  

We know that time period of the pendulum is   

Assuming the density of the object is greater than the density of the liquid i.e, ρ> ρ' 

(if the density of the object is less than the density of the liquid then the object would not sustain oscillation even if it moves at all and it would soon come to rest).

now if the density of the object is ρ and it is made to oscillate in a liquid of density ρ/8 then the effective value of acceleration due to gravity acting on the bob will be

 g' = g(1- density of sphere/density of liquid) = g(1-1/8) = 7g/8

thus you can observe the change in Time period!  

 

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Answer 2

Answer:

Time period of a simple pendulum on nonviscous fluid

Let L be the length of pendulum

p be the density of Bob

p' be that of liquid. Then time period of simple pendulum is

T=2π√( (L)÷((P-P')*g/P))

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Explanation: