A simple pendulum with brass Bob has a period t the Bob is now immersed in non viscous liquid is 1\8 of brass the time period of same pendulum will be
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the timeperiod of the same pendulum may be increased.
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Wo = d V g where d is density of brass and V the volume of pendulum
B = buoyant force = (d / 8) V g weight of liquid displaced
W = Wo - B apparent weight of pendulum in liquid
W = d V g (1 - 1/8) = 7 / 8 Wo
So the pendulum experiences an apparent gravitational acceleration of 7 g / 8
Since the period of the pendulum is given by
T = 2 pi * (L/g)^1/2
T / To = (g / (7 g / 8))^1/2 = (8 / 7)^1/2
The period increases due to an apparent decrease in the gravitational force.
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