Question

A simple screw Jack has Lever arm of 50 cm and pitch of 10 millimetre .it Lifts a load of 5 kilo Newton with an effort of 100 Newton. calculate the efficiency at this load .​

Answer 1

Answer:

Work done in one rotation = work done against gravity

i.e. F×2π×

2

1

=200×10×5×10

−3

F×2π=(mg)×pitch

F=

3.14

10

=3.18N