Question

A simple U tube contains mercury to the same level in
both of its arms. If water is poured to a height of
13.6 cm in one arm, how much will be the rise in
mercury level in the other arm?
Given : density of mercury = 13.6 x 103 kg m-3 and
density of water = 10 kg m-3.​

Answer 1

Answer:

Given,

Water height = 13.6 cm or, 0.136 m

Density of water = 1000 kgm^-3

Density of mercury = 13600 kgm^-3

Pressure exerted by water on the mercury = hpg

= (0.136*1000*10) Pa

= 1360 Pa

Height increased by the mercury on getting a pressure of 1360 Pa = hpg

1360 = (h*13600*10)

= 1360 = 136000h

= 0.01 m = Height

Hope this helps.