Physics, asked by siddhantsarthak4349, 18 days ago

A simply supported wood beam of rectangular cross section and span length 1.2 m carries a concentrated load P at midspan in addition to its own weight (see Fig. Q13). The cross
section has width 140 mm and height 240 mm. The weight density of the wood is 5.4 kN/m3
. Calculate the maximum permissible value of the load P, if (a) the allowable bending stress is 8.5 MPa, and (b) the allowable shear stress is 0.8 MPa.

Answers

Answered by shraddha200604
0

Answer:

= 250mm, L = 1.3m ,

Central point load = 'W' N

σb=7N/mm2andqmax=1N/mm2

Solution:

M = Max. B.M. = WL4=w×1.34=0.325W−N.m

S = Max S.F =. Reaction = W2N=0.5WN

For rectangular section,

A = b x d = 150 x 250 = 37500 mm2

I = bd312=150×250312=195.31×106mm4

ymax=d/2=2502=125mm

Value of 'W' for bending stress criteria

MI=σy∴M=σy×y

∴325W=7×195.31×106125

∴W=33653.41N=33.65kN

Value of 'W' for shear stress criteria

qmax=1.55A

∴1=1.5×0w37500=33.65kN

∴W=50000N−50kN

Safe Value of W = min, of A & B = 33.65 kN

Similar questions