A simply supported wood beam of rectangular cross section and span length 1.2 m carries a concentrated load P at midspan in addition to its own weight (see Fig. Q13). The cross
section has width 140 mm and height 240 mm. The weight density of the wood is 5.4 kN/m3
. Calculate the maximum permissible value of the load P, if (a) the allowable bending stress is 8.5 MPa, and (b) the allowable shear stress is 0.8 MPa.
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Answer:
= 250mm, L = 1.3m ,
Central point load = 'W' N
σb=7N/mm2andqmax=1N/mm2
Solution:
M = Max. B.M. = WL4=w×1.34=0.325W−N.m
S = Max S.F =. Reaction = W2N=0.5WN
For rectangular section,
A = b x d = 150 x 250 = 37500 mm2
I = bd312=150×250312=195.31×106mm4
ymax=d/2=2502=125mm
Value of 'W' for bending stress criteria
MI=σy∴M=σy×y
∴325W=7×195.31×106125
∴W=33653.41N=33.65kN
Value of 'W' for shear stress criteria
qmax=1.55A
∴1=1.5×0w37500=33.65kN
∴W=50000N−50kN
Safe Value of W = min, of A & B = 33.65 kN
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