Question

(a) Simply:
$\sf\{( {3x}^{2} - 6x + 5) + (2x - {2x}^{2} + 5)\} - ( {x}^{2} - 4x + 10)$

(b) Subtract:

= $\sf{4p}^{2}q - 3pq + {5pq}^{2} - 8p + 7p - 10$
from
= $\sf18 - 3p - 11q + 5pq - {2pq}^{2} + {5p}^{2}q$

Note:
- Kindly Dont Spam
- Need Quality Answer!​

Answer 1

A

$\sf\{( {3x}^{2} - 6x + 5) + (2x - {2x}^{2} + 5)\} - ( {x}^{2} - 4x + 10) \\ = {( {x}^{2} - 4x + 10)} - { ({x}^{2} - 4x + 10 )} \\ = 0$

Answer 2

${ \underline{ \boxed{ \blue{ \rm{Solution \: 1}}}}}$

Question:

• (a) Simply: $\sf\{( {3x}^{2} - 6x + 5) + (2x - {2x}^{2} + 5)\} - ( {x}^{2} - 4x + 10)$

Solution:

★ Expression:

$\sf\{( {3x}^{2} - 6x + 5) + (2x - {2x}^{2} + 5)\} - ( {x}^{2} - 4x + 10)$

• Now first let's solve the expression in the flower brackets

$\longrightarrow\tt \{( {3x}^{2} - 6x + 5) + (2x - {2x}^{2} + 5)\} - ( {x}^{2} - 4x + 10) \\ \\ \\ \longrightarrow\tt \: (3 {x}^{2} - 6x + 5 + 2x - 2 {x}^{2} + 5) - ( {x}^{2} - 4x + 10) \: \: \: \: \: \: \: \:$

• Now let's group the like terms in the first bracket

$\longrightarrow\tt \: (3 {x}^{2} - 2 {x}^{2} - 6x + 2x + 5 + 5) - ( {x}^{2} - 4x + 10) \\ \\ \\ \longrightarrow\tt( {x}^{2} - 4x + 10) - ( {x}^{2} - 4x + 10) \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

• Now as we've got the minus sign before the 2nd bracket let's multiply it with the expression in the second bracket and merge it with terms in first bracket

$\longrightarrow\tt \: ( {x}^{2} - 4x + 10 - {x}^{2} + 4x - 10)$

• Now let's group the like terms and simplify it again

$\longrightarrow\tt( \cancel{x}^{2} - \cancel{x}^{2} - 4x + 4x +\cancel 10 -\cancel 10) \\ \\ \\ \longrightarrow\tt( - 4x + 4x) \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \longrightarrow{ \boxed{ \frak{ 0 }} \star} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

• Hence, the answer is 0

${ \underline{ \boxed{ \blue{ \rm{Solution \: 2}}}}}$

Question:

• (b) Subtract:

$\sf{4p}^{2}q - 3pq + {5pq}^{2} - 8p + 7p - 10$

from

$\sf18 - 3p - 11q + 5pq - {2pq}^{2} + {5p}^{2}q$

Solution:

• Expression 1

$\sf18 - 3p - 11q + 5pq - {2pq}^{2} + {5p}^{2}q$

• Expression 2

$\sf{4p}^{2}q - 3pq + {5pq}^{2} - 8p + 7p - 10$

Let's subtract them now,

${\longrightarrow}\tt(\sf18 - 3p - 11q + 5pq - {2pq}^{2} + {5p}^{2}q) -( {4p}^{2}q - 3pq + {5pq}^{2} - 8p + 7p - 10 )$

• Let's multiply the sign minus with the second expression

${\longrightarrow}\tt(\sf18 - 3p - 11q + 5pq - {2pq}^{2} + {5p}^{2}q - {4p}^{2}q + 3pq - {5pq}^{2} + 8p - 7p + 10 )$

• Grouping like terms

${\longrightarrow}\tt(\sf18 + 10- 3p + 8p \:- 7p - 11q + 5pq - {2pq}^{2} + {5p}^{2}q - {4p}^{2}q + 3pq - {5pq}^{2} ) \\ \\ \\ \longrightarrow\sf(28 - 2p - 11q + 5pq - 2p {q}^{2} + 1 {p}^{2} q + 3pq - 5p {q}^{2} ) \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \longrightarrow\sf(28 - 2p - 11q + 5pq + 3pq - 2p {q}^{2} - 5p {q}^{2} + {p}^{2} q) \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \longrightarrow\sf(28 - 2p - 11q + 8pq - 7p {q}^{2} + {p}^{2} q )\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

• Hence solved.!!!