( a sin A + b sin B + c sin C)/ (a cos A + b cos B + c cosC)=R*(a2+b2+c2) /abc
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(i) asinA−bsinB=2R(sin2A−sin2B)=(2RsinC)(sin(A−B))=csin(A−B)
(ii) b−ccosAc−bcosA=acosCacosB=cosCcosB
(iii) a2sin(B−C)=4R2sin2Asin(B−C)
=[4R2sinA]sin(B+C).sin(B−C) ∵sinA=sin(B+C)]
=[4R2sinA][sin2B−sin2C]
=[(2RsinB)2−(2RsinC)2]sinA
=(b2−c2) sinA
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