Math, asked by sanabiaswas, 1 year ago

a sin(B-C)+b sin(C-A)+c sin(A-B)=0

Answers

Answered by nawazishrehan1
30
SinA . Sin(B - C) + SinB . Sin(C - A) + SinC . Sin(A - B)=0

=>SinA . (SinBCosC - CosBSinC) + SinB . (SinCCosA - CosCSinA) + SinC . (SinACosB - CosASinB)

=>SinASinBCosC -SinACosBSinC + SinBSinCCosA - SinBCosCSinA + SinCSinACosB - SinCCosASinB

All get cancelled

=>0

Hence Proved

Answered by harsh1234567892
21
SinA . Sin(B - C) + SinB . Sin(C - A) + SinC . Sin(A - B)=0

=>SinA . (SinBCosC - CosBSinC) + SinB . (SinCCosA - CosCSinA) + SinC . (SinACosB - CosASinB)

=>SinASinBCosC -SinACosBSinC + SinBSinCCosA - SinBCosCSinA + SinCSinACosB - SinCCosASinB

All get cancelled

=>0
Proved
plzz mark it as a brainlist
Similar questions