Question

a sin theta=3 and a cos theta=4 then a=​

Answer 1

Answer:

Sin theta=3/a

cos theta=4/a

Squaring both and adding we get

sin^2 theta+cos^2 theta=9/a^2+16/a^2

a^=25

a=5

Answer 2

Answer:

a = 5

Step-by-step explanation:

Given, a sin θ = 3, a cos θ = 4

On squaring both the given equations,

we get,

a² sin² θ = 9

a² cos² θ = 16

Let's add these two new equations,

⇒ a² sin² θ + a² cos² θ = 25

⇒ a² (sin² θ + cos² θ) = 25

⇒ a² x 1 = 25

⇒ a² = 25 (∵ sin² θ + cos² θ = 1)

⇒ a = 5