A sine wave voltage is applied across an inductor. when the frequency of the voltage is decreased, the current
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Answered by
1
Dear user,
If the opposition to applied voltage is increased, then current value is decreased.
Here,the opposition is due to reactance of capacitor.
Xc=12πfC
Xc=reactance of capacitor,
f=frequency of applied voltage.
Xc∝1f[since12πC=constant] (1)
From ohm's law,
V=IcXc
Xc=VIc
Xc∝1Ic[since V is constant] (2)
From (1)&(2);
1f∝1IC
Ic∝f
From above relation,
If the frequency of voltage is decreased, then current value is also decreased.
Hope it will help u....
If the opposition to applied voltage is increased, then current value is decreased.
Here,the opposition is due to reactance of capacitor.
Xc=12πfC
Xc=reactance of capacitor,
f=frequency of applied voltage.
Xc∝1f[since12πC=constant] (1)
From ohm's law,
V=IcXc
Xc=VIc
Xc∝1Ic[since V is constant] (2)
From (1)&(2);
1f∝1IC
Ic∝f
From above relation,
If the frequency of voltage is decreased, then current value is also decreased.
Hope it will help u....
Answered by
1
Answer:
Increase
Explanation:
Impedance will be given by :
Xl = 2πfL
(f being the frequency)
Hence, if frequency reduces consequently impedance(xL) reduces contributing to higher current
correct if wrong
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