Question

A single conservative force act on body of mass 1kg that moves along the x-axis the potential energy v(x) is given by v(x)=20+(x-2)^2 where x is in the meters . at x=5.0m the particle has a kinetic energy 20J then find
a) minimum value of x in meters
b)maximum value of x in meters
c)maximum potential energy in joules
d)maximum kinetic energy in joules

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Answer 1

Explanation:

Potential energy at x=5.0m is

U=20+(5−2)

2

=29J

∴ Mechanical energy

E=K+U=20+29=49J

Answer 2

A single conservative force F(x) acts on a 1.0-kg particle that moves along the x-axis. The potential energy U(x) is given by U(x)=20+(x-2)2 where x is in meters. At x=5.0m, the particle has a kinetic energy of 20J.