A single conservative force Fx acts on 2kg particle that moves along x-axis. The potential energy is given by : U=(x-4)2-16 x is in meter and U is in joule. At x=6m kinetic energy of the particle is 8J. Find maximum kinetic energy and values of x between which particle moves.
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The mechanical energy of system is 69 J.
Since the force applied on the body is conserved ,therefore its total mechanical energy is going to be same at all values of 'x'.
Therefore we can calculate its mechanical energy at any value of 'x'.
we do it at x=5m
Total energy =kinetic energy+potential energy.
=50+[15+(x−3)2] at x=5
=50+[15+(5−3)2]
=50+[15+4]
=69J
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