A single die is rolled twice. Find the probability of rolling an even number the first time and a number greater than 1 the second time. Find the probability of rolling an even number the first time and a number greater than 1 the second time.
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A = { getting an even number the first time and number greater than 1 the second time }
A = { (2,2)(2,3)(2,4)(2,5)(2,6)(4,2)(4,3)(4,4)(4,5)(4,6)(6,2)(6,3)(6,4)(6,5)(6,6) }
n(A) = 15 ; n(S) = 36
p(A) = n(A)/n(S) = 15/36
#Hassan
A = { (2,2)(2,3)(2,4)(2,5)(2,6)(4,2)(4,3)(4,4)(4,5)(4,6)(6,2)(6,3)(6,4)(6,5)(6,6) }
n(A) = 15 ; n(S) = 36
p(A) = n(A)/n(S) = 15/36
#Hassan
rekhasuri31:
Nonsense
Answered by
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Heya mate.. The answer is 15/36
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