A single discount equivalent to a discount series of 40% and 20o/o is
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3 discount of 10,20,40% discount
we will find net effective discount by :
net effective discount = a+b-ab/100
Case-I 20&40% discount first,,,
net discount = 20+40-(20x40)/100 = 52%
Case -II
& now effective discount of 52% and 10% is
= 52+10+(52x10)/100
= 62- 5.2%
= 56.8%
we will find net effective discount by :
net effective discount = a+b-ab/100
Case-I 20&40% discount first,,,
net discount = 20+40-(20x40)/100 = 52%
Case -II
& now effective discount of 52% and 10% is
= 52+10+(52x10)/100
= 62- 5.2%
= 56.8%
Answered by
2
Given : discount in series of 40% and 20%
To Find : A single equivalent discount
A) 49%
(B) 52%
(C) 53%
(D) None of these
Solution:
Let say Price before discount = P
40 % Discount = (40/100)P = 0.4P
price after one discount = P - 0.4P = 0.6P
20 % discount = (20/100)0.6P = 0.12P
Price after total Discount = 0.6P - 0.12P
= 0.48P
Net Discount = P - 0.48P = 0.52P
single equivalent discount = (0.52P/P) * 100
= 52 %
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