Question

A single electron in an ion head ionisation energy equal to 217.6 eV. What is the total number of neutrons present in one ion of it?

Answer 1

Ionization energy = 13.6 x z^2
217.6 = 13.6 x z^2
z^2 = 217.6/13.6
z = 4

element = Be
neutrons = 4

Answer 2

Answer:

answer is 5

Explanation:

no. of neutrons = mass - protons

using energy formula we get Z=4

Z = no. of protons= 4---- Be

mass number of be = 9

no. of neutrons = 9-4

therefore no. of neutrons = 5