Question

A single fixed pulley and a movable pulley both are separate used to lift a load of 50 kgf to the same height . compare the efforts applied​

Answer 1

Answer:

Explanation:

We know that in case of a single fixed pulley, the effort applied is equal to the load.

Hence,

E_f = L \\[0.5em]E

f

​

=L

In the case of a movable pulley the effort needed to lift a load is equal to half the load.

Em = \dfrac{L}{2} \\[0.5em] Em = \dfrac{50 kgf}{2} \\[0.5em] \Rightarrow E_m = 25kgf \\[0.5em]E

m

​

=

2

L

​

E

m

​

=

2

50kgf

​

⇒E

m

​

=25kgf

Hence, the ratio of efforts applied by the respective pulley is

\dfrac{Ef}{Em} = \dfrac{2}{1} \\[0.5em]

E

m

​

E

f

​

​

=

1

2

​

Therefore, Ef : Em = 2 : 1

Answer 2

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