Question

A single-lane street 10 ft wide goes through a semicircular tunnel with radius 9 ft. How high
is the tunnel at the edge of each lane? Round off to two decimal places.

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Answer 1

Step-by-step explanation:

Given A single-lane street 10 ft wide goes through a semi circular tunnel with radius 9 ft. How high is the tunnel at the edge of each lane? Round off to two decimal places.

• So the equation of the circle in the tunnel is x^2 + y^2 = r^2
• So the height of the tunnel is y  
• So radius of the tunnel = r = 9 ft
• The height at each lane goes through a semi circular tunnel and so  
•                   x = 10 / 2 ft
•                     = 5 ft
•    So x^2 + y^2 = r^2
•     5^2 + y^2 = 9^2
•     25 + y^2 = 81
•       Or y^2 = 81 – 25
•       Or y^2 = 56
•      Or y = √56
•     Or y = 7.48 ft

Reference link will be

https://brainly.ph/question/2897132