Question

A single letter is selected at random from the word Ranikhet
find the probability that the word is a
b) consonant
a) vowel​

Answer 1

Answer:

Step-by-step explanation:

The word Ranikhet has a total of 8 letters 3 of these are vowels and 5 are consonants.

p(e)=favorable outcomes/total number of outcomes

P(consonant)=favorable outcomes/total number of outcomes=5/8

P(vowel)=favorable outcomes/total number of outcomes=3/8

Answer 2

Number of consonants : 5

Number of vowels : 3

Total no. of letters : 8

Probability of the letter picked for vowels is 3/8

Probability of letter picked for consonants is 5/8

So there is more chance of picking a consonant than a vowel.