Physics, asked by anjelinadebbarma1, 5 hours ago

A single movable pulley is to be used for lifting a load of 80kgf .The required effort is​

Answers

Answered by aastha12349
1

Answer:

Load to be lifted F

load

=50 kgf

Case 1 : Fixed pulley is used.

MA for single fixed pulley MA=1

Thus effort applied by the boy F

effort

=

MA

F

load

=

1

50

=50 Kgf

Case 2 : Movable pulley is used.

MA for movable pulley MA=2

Thus effort applied by the boy F

effort

=

MA

F

load

=

2

50

=25 Kgf

So, effort to be applied by the boy is less in case when he used a movable pulley because MA for a movable pulley is greater than 1.

Explanation:

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Answered by samriddhipal5
0

Answer:

40kgf

Explanation:

Mechanical Advantage =Load/Effort

Effort E1 Applied

Load/M.A.= 80/1=80kgf

For a single movable pulley

L=80kgf

M.A.=2

Effort 2 applied

Load/M.A.=80/2=40kgf

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