Question

A single phase 50Hz transformer has 40 primary truns and 520 secondary truns the cross sectional area of core is 270sqcm when primary winding is connected to a 300volts supply determine the max value of flux density in the core the voltage induced in secondary winding

Answer 1

Answer:

602 hz

Explanation:

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Answer 2

3kV, 1.5 Tesla

Explanation:

We have equation $E_{1} = 4.44 f \phi_{m}N_{1}$

this gives us the value of phi as 0.04505 Weber

We also have $\phi_{m} = B_{m}*A$

this gives us max flux density as 1.50 Tesla

from $\frac{V_{1} }{V_{2} } = \frac{N_{1} }{N_{2} }$

we get the value of Voltage $V_{2}$ as 3000kV or 3kV