Question

A single slit Fraunhofer diffraction pattern is formed using white light. For what wavelength of light does the second minimum coincide with the third minimum for the wavelength 4000 Aº?​

Answer 1

Answer:

x=

2a

(2n+1)λD

​

For red light x=

2a

(4+1)D

​

×6500

For unknown wavelength of light,

x=

2a

(6+1)D

​

×λ

Accordingly,

∴5×6500=7×λ

⇒λ=

7

5

​

×6500

=4642.8

A

∘

.

Explanation:

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